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[parent] GRE Physics Companion: Degrees of Freedom in Mechanics (Example)

GRE Physics Companion: Degrees of Freedom in Mechanics

This entry is the GRE-oriented companion to M00-07. The core article develops the mechanics meaning of degrees of freedom, constraints, generalized coordinates, and configuration space. Here the emphasis is rapid recognition and counting.

1 Fast counting strategy

For standard GRE-style mechanics problems, use the following order:

  1. Count the coordinates before constraints.
  2. Identify only independent constraints.
  3. For regular holonomic constraints, use
    f = n −  m.
    (1)

  4. Check whether the system is a familiar special case such as a particle on a curve, planar rigid body, or spatial rigid body.
  5. Do not count velocities as additional configuration degrees of freedom.

PIC

Figure 1. GRE-speed triage for ordinary degree-of-freedom counting problems.

Useful counts to recognize immediately are

particle on line : f = 1,
(2)

particle in plane :   f = 2,
(3)

free particle in 3D :   f = 3,
(4)

planar rigid body  :  f =  3,
(5)

and

spatial rigid body :  f =  6.
(6)

2 Common GRE traps

  1. A coordinate representation can use more numbers than the physical number of degrees of freedom.
  2. A constraint removes a degree of freedom only if it is independent of the other constraints.
  3. position and velocity are both needed for a dynamical state, but velocity does not add configuration degrees of freedom.
  4. A four-component unit quaternion represents only three rotational degrees of freedom because of its normalization constraint.
  5. A coordinate that is cyclic in a Lagrangian still represents a degree of freedom.

PIC

Figure 2. High-frequency GRE traps: written variables, state variables, and physical degrees of freedom are not the same count.

3 Worked GRE example 1: particle on a sphere

A particle moves on the surface of a sphere of fixed radius R. How many degrees of freedom describe its configuration?

Start with Cartesian coordinates (x,y,z), so

n = 3.
(7)

The spherical surface imposes one independent constraint,

x2 + y2 + z2 = R2.
(8)

Therefore

f = 3 − 1 = 2.
(9)

A convenient coordinate pair is (𝜃,ϕ).

GRE shortcut: a particle confined to a smooth two-dimensional surface has two local configuration degrees of freedom.

4 Worked GRE example 2: position plus quaternion

A rigid spacecraft is represented numerically by three Cartesian position coordinates and a four-component unit quaternion for orientation. How many physical configuration degrees of freedom are present?

The position contributes three degrees of freedom. The quaternion has four components but obeys

q2 + q2+  q2+ q2 = 1.
 0    1    2   3
(10)

Thus it contains only three independent orientation parameters. Therefore

f = 3 + 3 = 6.
(11)

The answer is not seven. The numerical representation is redundant because of the unit-norm constraint.

5 GRE-speed questions

M00-07G-Q01

Two point masses move in a plane and are connected by a rigid massless rod of fixed length. How many configuration degrees of freedom does the system have?

(A) 2 (B) 3 (C) 4 (D) 5

M00-07G-Q02

Five independent particles move freely in three-dimensional space. The system has how many configuration degrees of freedom?

(A) 5 (B) 10 (C) 15 (D) 30

M00-07G-Q03

A mechanical system has three configuration degrees of freedom. In the usual Hamiltonian formulation, what is the dimension of its phase space?

(A) 3 (B) 4 (C) 6 (D) 9

M00-07G-Q04

A simple pendulum is described using Cartesian bob coordinates (x,y) with the constraint x2 + y2 = L2. The number of configuration degrees of freedom is

(A) 0 (B) 1 (C) 2 (D) 3

M00-07G-Q05

Which statement is correct for a free rigid body in three-dimensional space?

(A) It has three degrees of freedom because its center of mass has three coordinates.

(B) It has four degrees of freedom because a quaternion has four components.

(C) It has six degrees of freedom: three translational and three rotational.

(D) It has nine degrees of freedom because a rotation matrix has nine entries.

6 Answers and brief rationales

  1. Q01: B. Four planar particle coordinates minus one fixed-distance constraint gives three.
  2. Q02: C. Each free particle contributes three, so f = 3N = 15.
  3. Q03: C. Standard phase space has coordinates (qi,pi) and therefore dimension 2f = 6.
  4. Q04: B. Two coordinates minus one independent geometric constraint leaves one degree of freedom.
  5. Q05: C. Numerical orientation representations may be redundant, but physical orientation has three independent parameters.

7 Test-day summary

For ordinary GRE mechanics questions, the most useful mental rule is

DOF  =  independent  con figuration variables after constraints.
(12)

Do not confuse that count with the number of written symbols or with the number of variables required to specify the full dynamical state.

References

[1]   J. R. Taylor, Classical Mechanics, University Science Books, 2005.

[2]   J. B. Marion and S. T. Thornton, Classical Dynamics of Particles and Systems, 5th ed., Brooks/Cole, 2004.

[3]   PhysicsLibrary, M00-07: Degrees of Freedom in Mechanics, core companion article.


"GRE Physics Companion: Degrees of Freedom in Mechanics" is owned by bloftin.
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Other names:  M00-07G
Keywords:  GRE physics, degrees of freedom, constraints, generalized coordinates, rigid body, configuration space, phase space

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Cross-references: matrix, center of mass, dimension, Hamiltonian, masses, parameters, two-dimensional, Cartesian coordinates, Lagrangian, quaternion, unit, position, representation, velocities, rigid body, particle, system, regular, generalized coordinates, mechanics, M00-07

This is version 1 of GRE Physics Companion: Degrees of Freedom in Mechanics, born on 2026-09-27.
Object id is 1307, canonical name is GREPhysicsCompanionDegreesOfFreedomInMechanics.
Accessed 23 times total.

Classification:
Physics Classification: 45.20.Jj (Lagrangian and Hamiltonian mechanics)
 45.20.-d (Formalisms in classical mechanics)
 45.40.-f (Dynamics and kinematics of rigid bodies)
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