Wave Mechanics: Deriving the 1D String Wave Equation from Newton’s Second Law
WM13 introduced the derivative structure
and showed that translating profiles such as F(x − ct) satisfy it. That was a kinematic
result: it described a mathematical relation obeyed by a shape-preserving traveling
disturbance.
WM14 asks the dynamical question:
The answer comes directly from Newton’s second law. A curved string has slightly different
Tension directions at neighboring points. The difference between those tension directions produces
a transverse force. That force is proportional to the local curvature of the string, and Newton’s
second law then turns curvature into transverse acceleration. Under the ideal assumptions
developed below, this leads to
or
Comparison with the standard one-dimensional wave equation gives
This derivation is standard in treatments of waves on stretched strings and is a canonical example
of how a continuum partial differential equation emerges from Newtonian mechanics
[1, 2, 3, 5].
1 The physical model
Consider a thin flexible string stretched primarily along the x direction. Let
denote its transverse displacement from equilibrium.
The derivation uses several assumptions. They are not merely mathematical conveniences; they
define the physical model.
- The string is continuous and perfectly flexible, with negligible bending stiffness.
- The string has uniform linear mass density μ.
- The equilibrium tension magnitude T is approximately constant along the string.
- motion is transverse; longitudinal motion is neglected to first order.
- The slope is small:
- Damping, gravity, and distributed external transverse forces are neglected.
The most important approximation is the small-slope condition. The displacement itself need not
be zero, but neighboring pieces of the string must make only small angles with the equilibrium x
direction. For a sinusoidal wave, the small-slope requirement is roughly controlled by the
dimensionless quantity Ak.
These assumptions produce the linear string wave equation. If the slopes become large, the tension
varies strongly, the string stretches significantly, or bending stiffness matters, additional nonlinear
or higher order terms appear.
2 Choose a short string element
Select a small piece of string extending from x to x + Δx.
If μ is the mass per unit equilibrium length, then the mass of this element is approximately
The element is pulled by the rest of the string at both ends. Because an ideal string can sustain
tension but not bending moment, the tension force at each end acts tangent to the local string
direction.
Figure. A short string element between x and x + Δx. The neighboring string pulls
tangentially on the two ends with approximately equal tension magnitude T, but the
directions differ because the string is curved.
Let the local tangent angles be 𝜃L at the left end and 𝜃R at the right end.
3 Geometry connects tangent angle to spatial slope
At any point on the string, the slope of the tangent line is
This relation is geometric and exact for the graph u(x,t) at a fixed time.
The small-slope assumption gives
so the standard small-angle approximations apply:
Therefore
This is the step that linearizes the force law.
A more exact relation would be
which reduces to sin 𝜃 ≃ ux when |ux|≪ 1.
4 Resolve the tension forces
The right-hand tension contributes a transverse component
while the left-hand tension contributes
The net transverse force on the element is therefore
Using the small-slope approximation,
In coordinate form,
The horizontal components are
For small slopes,
so the horizontal components cancel to first order. This is consistent with the model assumption
that the leading motion is transverse and that the tension magnitude can be treated as
constant.
5 Curvature produces a transverse force
Rewrite the transverse force as
As the element becomes arbitrarily short,
Thus
This equation contains the central physical idea:
If the string is locally straight, uxx = 0, the tension directions balance in the transverse direction
and there is no transverse net force from tension. If the string is curved, the two tension vectors do
not cancel transversely.
Figure. For a concave-down string element, uxx < 0. The tension imbalance points
downward, so the transverse acceleration is also negative. The signs of curvature and
acceleration therefore agree in the linear string model.
6 Apply Newton’s second law
The transverse acceleration of the material element is
The element mass is
Newton’s second law in the transverse direction is
Substitute the force and mass expressions:
Cancel the nonzero element length Δx:
Finally divide by μ:
This is the one-dimensional linear wave equation for an ideal stretched string.
Figure. The derivation chain from string geometry to Newton’s second law. A difference in
local slope creates a transverse tension imbalance; in the continuum limit that slope
difference becomes uxx.
7 Identify the wave speed
The standard one-dimensional wave equation has the form
The string equation is
Therefore
and
The positive root is used for the speed magnitude. Direction is carried by the traveling-wave
form F(x − ct) or G(x + ct) rather than by assigning a negative value to the speed
magnitude.
This result says:
- increasing the tension makes waves travel faster;
- increasing the mass per unit length makes waves travel slower.
More precisely,
when μ is fixed, and
when T is fixed.
Figure. Wave speed on an ideal string scales with the square root of tension and with the
inverse square root of linear mass density.
8 Dimensional check
A correct physical equation must have consistent units.
Tension has units of force:
Linear mass density has units
Therefore
Taking the square root gives
which is the correct dimension for speed.
The differential equation is also dimensionally consistent. If u is a displacement,
and
9 The equation expresses a local feedback law
The string equation can be read physically as
A region that is locally concave upward has
so the transverse acceleration is upward. A region that is locally concave downward
has
so the transverse acceleration is downward.
At an inflection point,
so the string has no transverse acceleration from the local tension imbalance at that instant, even
though the displacement or velocity at that point may be nonzero.
This is more informative than viewing the wave equation as a purely symbolic relation between
second derivatives. The equation is a local Newtonian law: curvature produces force, force
produces acceleration, and the resulting motion changes the curvature at neighboring
points.
10 Why the equation is linear
The equation
is linear in the field u. If u1 and u2 are solutions for the same constant T and μ, then any linear
combination
is also a solution.
This mathematical linearity is the reason the superposition principle from WM09 works for the
ideal string model.
The linearity comes from the modeling assumptions. In particular, the approximation
replaces the exact geometric force relation by one that is linear in the slope. If the slope is not
small, that simplification fails and nonlinear effects can appear.
11 Consistency with a translating disturbance
WM13 showed that a sufficiently smooth right-moving profile
obeys
The mechanical derivation now says that the stretched string obeys
The two are consistent when
Thus the traveling-wave speed is no longer just a parameter in a chosen function. The mechanical
properties of the string determine it.
A sinusoidal wave
therefore satisfies
or
For the ideal string this is a nondispersive relation: all sinusoidal components have the same phase
speed ω∕k = c within the model.
12 The role of initial and boundary conditions
The wave equation does not by itself determine one unique motion. WM12 made that point
explicit.
For a finite string we still need initial data such as
and
plus boundary conditions such as
for a fixed-fixed string.
The local differential law
tells us how the interior evolves. The initial and boundary conditions select the particular physical
solution.
13 What changes outside the ideal-string assumptions?
The derivation also shows where more complicated models come from.
If the tension varies with position, a more general linearized string equation has the
structure
rather than simply Tuxx.
If bending stiffness is important, as in a beam or stiff wire, higher spatial derivatives appear. If
damping is important, velocity-dependent terms appear. If slopes become large, geometric
nonlinearities appear. If external forcing acts along the string, a forcing term appears on the
right-hand side.
Thus
should be understood as the governing equation of a specific idealized physical system, not as a
universal equation for every one-dimensional object that can vibrate.
14 Worked example 1: compute wave speed
A string is under tension
and has linear mass density
The wave speed is
| c | =  | (66)
|
| = m/s | (67)
|
| = m/s | (68)
|
| ≈ 122 m/s . | (69) |
15 Worked example 2: scaling with tension and density
Suppose an ideal string initially has speed c0.
If the tension is increased by a factor of four while μ stays fixed,
So quadrupling tension doubles wave speed.
If instead the linear density is increased by a factor of four while T stays fixed,
So quadrupling linear density halves wave speed.
16 Worked example 3: find the required tension
A string has
and must support waves at speed
From
we obtain
| T | = μc2 | (75)
|
| = (0.020)(75)2 N | (76)
|
| = 112.5 N . | (77) |
17 Worked example 4: connect the wave equation to k and ω
Consider
The Wavenumber and angular frequency are
Hence
If the string has
then the required tension is
| T | = μc2 | (82)
|
| = (0.010)(30)2 N | (83)
|
| = 9.0 N . | (84) |
The same conclusion follows from matching the second derivatives:
Substitution into
gives
which is equivalent to
18 Common mistakes
- Mistake: using displacement itself as the restoring-force variable. For an ideal
stretched string, the local tension imbalance is controlled by curvature uxx, not directly
by u.
- Mistake: assuming ux is the wave speed. It is spatial slope.
- Mistake: assuming ut is the propagation speed. For string displacement it is the
transverse material velocity at fixed x.
- Mistake: forgetting that the mass of the small element is μΔx.
- Mistake: adding the two vertical tension components instead of taking their signed
difference.
- Mistake: using c = T∕μ. The correct speed is the square root c =
.
- Mistake: treating constant tension as exact for arbitrary large slopes. It is part of the
linear ideal-string approximation.
- Mistake: thinking the wave equation alone fixes the motion. Initial and boundary
conditions are still required.
19 What WM14 adds to the wave-mechanics language
The earlier lessons built the mathematical structure of a wave. WM14 supplies the mechanical
cause for that structure in an ideal string.
The chain is
Quantitatively,
and therefore
This is the first point in the series where the one-dimensional wave equation has been obtained
from a physical law rather than merely recognized as a relation satisfied by a chosen traveling
waveform.
20 References
References
[1] A. P. French, Vibrations and Waves, M.I.T. Introductory Physics Series, W. W.
Norton & Company, 1971.
[2] Frank S. Crawford, Jr., Waves, Berkeley Physics Course, Volume 3, McGraw-Hill,
1968.
[3] William Moebs, Samuel J. Ling, and Jeff Sanny, University Physics, Volume 1,
OpenStax, 2016, Section 16.3, “Wave Speed on a Stretched String.”
[4] William Moebs, Samuel J. Ling, and Jeff Sanny, University Physics, Volume 1,
OpenStax, 2016, Section 16.2, “Mathematics of Waves.”
[5] Massachusetts Institute of Technology, 8.03SC Physics III: Vibrations and Waves -
The Physics of Waves, Fall 2016, MIT OpenCourseWare, material on the one-dimensional
wave equation and transverse waves on a string.