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[parent] Wave Mechanics Examples: Wave Speed (Example)

Wave Mechanics Examples: Wave Speed

This companion article provides self-study exercises for WM08, wave mechanics: Wave speed. The problems consolidate the equivalent kinematic relations

|-----------------|
c = ω- = -λ = f λ |
-----k---T--------|
(1)

and the signed constant-phase velocities for one-dimensional sinusoidal waves. These relations are standard in introductory wave mechanics [1234].

All exercises are stated before the worked solutions. The set remains within the WM08 scope: it treats wave speed kinematically and does not yet derive the medium-dependent dynamical value of c from a wave equation.

How to use this problem set

Attempt every exercise in Part I before consulting Part II. For each numerical problem, identify whether the given information is temporal (T,f,ω), spatial (λ,k), or both. For direction questions, distinguish the positive speed magnitude c from the signed phase velocity.

WM08 relations permitted in this set:
     ω    λ                              2π
c =  --= -- = f λ,    ω  = 2πf,     k =  --.
     k   T                               λ
For k > 0 and ω > 0,
                                          ω-
kx −  ωt + ϕ = constant   ⇒    vphase = + k,
while
                                          ω
kx +  ωt + ϕ = constant   ⇒    vphase = − -.
                                          k
The speed magnitude is c = |vphase|.

Part I: Exercises

Exercise 1: Frequency and wavelength

A wave has frequency 4.0 Hz and wavelength 1.5 m.

  1. Calculate its propagation speed.
  2. State the physical meaning of the result in one sentence.
  3. If the wavelength doubled while the frequency remained fixed, what would happen to the speed implied by the kinematic relation?

Exercise 2: Angular frequency and angular wavenumber

A right-moving sinusoidal wave has

ω = 18 rad∕s,    k =  6.0 rad∕m.

  1. Calculate c from ω∕k.
  2. Determine f and λ.
  3. Verify the speed independently using .

Exercise 3: Infer wavelength from speed and frequency

A periodic disturbance travels at 150 ms and has frequency 60 Hz.

  1. Find its wavelength.
  2. Find its period.
  3. How far does a fixed phase point move during one period?

Exercise 4: Read speed from a constant-phase track

The figure shows the trajectory of one constant-phase feature in an xt diagram.

PIC

Figure. A constant-phase feature passes through two marked events. The horizontal and vertical differences are shown separately so that the slope can be read without overlapping the trajectory.

  1. Read Δx and Δt from the graph.
  2. Calculate the signed propagation velocity.
  3. State the propagation direction.
  4. Give the positive speed magnitude.

Exercise 5: Direction from the wave equation

For each wave, assume k > 0 and ω > 0. Determine the signed phase velocity and propagation direction.

  1. u = A cos(kx ωt).
  2. u = A cos(kx + ωt).
  3. u = A cos(kx ωt + π∕4).
  4. Explain why the minus sign in front of A in part (c) does not reverse the propagation direction.

Exercise 6: One wavelength in one period

A crest of a periodic wave is at x = 1.2 m at t = 0.40 s and at x = 3.0 m at t = 1.00 s. Suppose the two events refer to the same crest and are separated by exactly one period.

  1. Determine the wavelength.
  2. Determine the period.
  3. Determine the speed using λ∕T.
  4. Determine the frequency and verify the result using .

Exercise 7: Different waves, same speed

The following two spatial profiles belong to waves traveling in the same medium. Their frequencies are f1 = 1.0 Hz and f2 = 2.0 Hz.

PIC

Figure. Two waves with different wavelengths. The wavelength markers are placed below the curves to keep the graph readable.

  1. Read λ1 and λ2 from the figure.
  2. Calculate the speed of each wave.
  3. Are the speeds the same?
  4. Explain how the frequency and wavelength compensate one another.

Exercise 8: Are the measured quantities self-consistent?

A laboratory report lists

λ = 0.50 m,     f =  8.0 Hz,     k = 4π rad∕m,      ω = 16π rad∕s.

  1. Check whether k agrees with the listed wavelength.
  2. Check whether ω agrees with the listed frequency.
  3. Calculate c using .
  4. Calculate c using ω∕k.
  5. State whether the four measurements are mutually consistent.

Exercise 9: Wave speed versus material speed

The figure shows a transverse pulse moving along a string while a marked material point on the string moves vertically.

PIC

Figure. The disturbance propagates horizontally, while the marked string element moves locally in the transverse direction. The arrows are separated to emphasize the two different velocities.

  1. Which arrow represents the wave propagation velocity?
  2. Which arrow represents a local material velocity?
  3. Why are these velocities not generally equal or even parallel?
  4. Which velocity is described by c = in this lesson?

Exercise 10: Full wave equation synthesis

Consider

u(x,t) = 0.020 cos(5 πx − 20πt + π∕6 ),

where u and x are in meters and t in seconds.

Determine:

  1. the propagation direction;
  2. k and ω;
  3. λ and f;
  4. the wave speed using ω∕k;
  5. the wave speed using ;
  6. whether the two results agree.

Exercise 11: Dimensional checks

Decide whether each proposed expression could represent a speed. Give a brief reason.

  1. .
  2. f∕λ.
  3. ω∕k.
  4. k∕ω.
  5. λ∕T.

Exercise 12: Constant phase without memorizing the sign rule

A wave has phase

𝜃(x,t) = 3x + 12t + ϕ,

where the coefficient of x is in rad/m and the coefficient of t is in rad/s.

  1. Hold 𝜃 constant and solve for x(t).
  2. Determine the signed phase velocity.
  3. Determine the positive speed magnitude.
  4. State the direction of propagation.
  5. Explain how this calculation reproduces the usual sign convention.

Exercise 13: A medium with fixed propagation speed

In a particular nondispersive approximation, waves travel at 12 ms.

  1. Find the wavelength when f = 3.0 Hz.
  2. Find the wavelength when f = 6.0 Hz.
  3. Find the wavelength when f = 12 Hz.
  4. Describe the trend between frequency and wavelength at fixed speed.
  5. Does this trend imply that increasing frequency caused the speed to change?

Exercise 14: Capstone—reconstruct the propagation speed

A sinusoidal wave is observed experimentally. Consecutive crests in a spatial snapshot are separated by 0.75 m. At one fixed location, consecutive maxima in the time history are separated by 0.30 s. In an independent measurement, a chosen crest moves 2.50 m in 1.00 s.

  1. Determine λ.
  2. Determine T and f.
  3. Calculate c using λ∕T.
  4. Calculate c using .
  5. Calculate the crest speed from the independent position measurement.
  6. Are all three speed estimates consistent?
  7. Calculate k and ω, then verify the same speed using ω∕k.
  8. Explain why agreement among all four methods is a strong internal consistency check on the measurements.

Part II: Complete Worked Solutions

Solution 1: Frequency and wavelength

Given

f = 4.0Hz,     λ =  1.5m,

we use

c = fλ.

  1.          −1           |-------|
c = (4.0s  )(1.5m ) = -6.0-m-∕s .
  2. A recognizable phase feature of the wave advances 6.0 m each second.
  3. If f remains fixed while λ doubles, then the product doubles. The kinematic relation would therefore imply that c doubles. Whether such a change is physically allowed depends on the system; WM08 itself does not specify the dynamics that set c.

Solution 2: Angular frequency and angular wavenumber

  1.                       |-------|
c = ω- = -18-rad∕s- = |3.0 m ∕s.
    k    6.0 rad ∕m    ---------
  2.      ω     18   |--------|
f =  ---=  ---≈ -2.86Hz--,
     2π    2π

    and

        2π-   2π-   |--------|
λ =  k  = 6.0 ≈ -1.047m--.
  3.                      |---------|
fλ ≈  (2.86)(1.047) ≈ -3.00m-∕s-.

    The two methods agree apart from rounding.

Solution 3: Infer wavelength from speed and frequency

  1.                     |------|
λ =  c-= 150-m-∕s = |2.5m  .
     f    60 s−1    -------
  2.      1-   --1---   |--------−-2-|
T =  f =  60s− 1 = 1.67-×-10---s .
  3. During one period, the same phase feature moves one wavelength, so
    |-----------|
-Δx-=--2.5m--.

Solution 4: Read speed from a constant-phase track

From the marked events in the figure,

Δx  = 6m,      Δt = 2 s.

  1. The graph directly gives the changes above.
  2.          Δx--  6-m-   |-------|
vphase = Δt  =  2s  = -+3-m-∕s .
  3. The positive sign means propagation toward increasing x.
  4. The speed magnitude is
    |----------|
-c =-3m-∕s-.

Solution 5: Direction from the wave equation

  1. Constant phase gives kx ωt = constant, so
               ω
vphase = + -.
           k

    The wave moves toward positive x.

  2. Constant phase gives kx + ωt = constant, so
               ω-
vphase = − k.

    The wave moves toward negative x.

  3. The internal phase still contains kx ωt, so
    vphase = + ω.
           k

    The wave moves toward positive x.

  4. Multiplying the displacement by 1 changes crest locations into trough locations, equivalent to a phase offset of π. It does not change the sign of the kx and ωt terms, so the propagation direction is unchanged.

Solution 6: One wavelength in one period

The spatial change of the same crest is

Δx  = 3.0 − 1.2 =  1.8 m,

and the elapsed time is

Δt =  1.00 − 0.40 = 0.60 s.

Because the events are separated by one full period,

λ = Δx,      T =  Δt.

  1. |----------|
-λ-=-1.8m--.
  2. |----------|
T  = 0.60s .
------------
  3.                 |--------|
c = λ- = -1.8- = |3.0m ∕s .
    T    0.60   ---------
  4. f =  1-=  -1-- ≈ 1.67 Hz.
     T    0.60

    Then

                       |-------|
fλ ≈ (1.67)(1.8) ≈ 3.0 m∕s .
                   ---------

Solution 7: Different waves, same speed

From the graph,

λ1 = 4 m,     λ2 = 2 m.

  1. The wavelength readings are the values above.
  2. For wave 1,
                          |--------|
c1 = f1λ1 = (1.0)(4 ) =-4.0m-∕s-.

    For wave 2,

                          |--------|
c2 = f2λ2 = (2.0)(2 ) =|4.0m ∕s .
                      ---------
  3. Yes. The speeds are identical.
  4. Doubling the frequency while halving the wavelength leaves the product unchanged.

Solution 8: Are the measured quantities self-consistent?

  1. 2π     2π
--- = ---- = 4 πrad ∕m,
 λ    0.50

    which agrees with the listed k.

  2. 2πf  = 2π (8.0) = 16π rad∕s,

    which agrees with the listed ω.

  3.                        |-------|
c = fλ = (8.0)(0.50 ) = 4.0m-∕s-.
  4.     ω    16π    |-------|
c = -- = ---- = -4.0-m-∕s .
    k     4π
  5. Yes. Both the defining relations and the two speed calculations agree, so the four listed measurements are mutually consistent.

Solution 9: Wave speed versus material speed

  1. The horizontal arrow following the pulse represents the wave propagation velocity.
  2. The vertical arrow at the marked string element represents a local material velocity.
  3. A wave is a propagating pattern. The medium can oscillate locally while the pattern moves through it, so the two velocities need not have the same magnitude or direction.
  4. The relation c = describes the propagation speed of the wave pattern or a constant-phase feature.

Solution 10: Full wave equation synthesis

The wave is

u(x,t) = 0.020 cos(5 πx − 20πt + π∕6 ).

  1. The phase contains kx ωt, so the wave propagates toward positive x.
  2. k = 5π rad∕m,      ω = 20 πrad ∕s.
  3.      2π    |------|
λ =  5π-=  0.40-m-,

    and

         20π    |-----|
f =  ----=  10-Hz-.
     2 π
  4.     20π    |-------|
c = ----=  4.0 m∕s .
    5π     ---------
  5.                 |--------|
c = (10)(0.40 ) =|4.0m ∕s .
                ---------
  6. Yes. The two forms give the same result.

Solution 11: Dimensional checks

  1. has units
     − 1
s  m  = m ∕s,

    so it can represent a speed.

  2. f∕λ has units 1(m s), not speed.
  3. ω∕k has units
    rad∕s
-------= m ∕s,
rad∕m

    so it can represent a speed.

  4. k∕ω has units sm, the reciprocal of speed.
  5. λ∕T has units ms, so it can represent a speed.

Solution 12: Constant phase without memorizing the sign rule

Set

3x + 12t + ϕ = 𝜃0.

Then

3x = 𝜃0 − ϕ − 12t,

so

       𝜃0 − ϕ
x (t) = -------− 4t.
          3

  1. The expression above is the constant-phase trajectory.
  2. Its slope is
    |----------------|
-vphase =-−-4m-∕s-.
  3. |----------|
-c =-4m-∕s-.
  4. The negative sign means motion toward decreasing x.
  5. Because the phase contains kx + ωt, solving for constant phase necessarily produces a negative slope. This is the origin of the usual sign rule.

Solution 13: A medium with fixed propagation speed

At fixed c,

     c-
λ =  f.

  1.      12   |------|
λ = --- = -4.0m--.
    3.0
  2.           -------
λ = -12 = |2.0m  .
    6.0   -------|
  3.      12-  |-----|
λ =  12 = -1.0-m--.
  4. At fixed speed, wavelength is inversely proportional to frequency. Doubling f halves λ.
  5. No. In this exercise the speed was stipulated to remain fixed. The changing wavelength is what allows to remain constant.

Solution 14: Capstone—reconstruct the propagation speed

The spatial data give

λ = 0.75 m.

The temporal data give

T  = 0.30s.

  1. ------------
|λ = 0.75 m .
------------|
  2. |----------|                |--------|
|T = 0.30 s,     f = --1- ≈ |3.33Hz  .
------------         0.30   ---------
  3.      λ    0.75    |--------|
c = -- =  ----=  2.50-m-∕s .
    T     0.30
  4.                          |--------|
c = f λ ≈ (3.33)(0.75 ) ≈ 2.50-m∕s-.
  5. The crest-position measurement gives
        2.50m    |---------|
c = -------= -2.50m-∕s-.
    1.00 s
  6. Yes. The three methods agree.
  7.      2π
k =  ----≈  8.38rad∕m,
     0.75

    and

    ω =  2πf ≈  20.94 rad∕s.

    Therefore

    ω-   20.94-  |---------|
k ≈   8.38  ≈ -2.50m-∕s-.
  8. Agreement shows that the measured spatial period, temporal period, crest displacement, and angular quantities all describe the same translating wave. A disagreement would signal either measurement error or an incorrect model assumption.

What this set completes

WM08E1 closes the first self-study block of the Wave Mechanics series. After WM00–WM08 and their companions, the student should be able to move freely between

T,   f,  ω,     λ,   k,     c,

and interpret the sinusoidal traveling-wave phase

kx ∓  ωt + ϕ.

The next block begins with WM09 and develops the two-variable field u(x,t) more formally, leading eventually to partial derivatives and the one-dimensional wave equation.

References

References

[1]   A. P. French, Vibrations and Waves, M.I.T. Introductory Physics Series, W. W. Norton & Company, 1971.

[2]   Frank S. Crawford, Jr., Waves, Berkeley Physics Course, Volume 3, McGraw-Hill, 1968.

[3]   Samuel J. Ling, Jeff Sanny, and William Moebs, University Physics, Volume 1, OpenStax, 2016, Chapter 16, especially Sections 16.1–16.2 and the Chapter 16 key equations.

[4]   Richard P. Feynman, Robert B. Leighton, and Matthew Sands, The Feynman Lectures on Physics, Volume I, Chapter 47, “Sound. The wave equation,” especially Sections 47–1 and 47–4.

[5]   Massachusetts Institute of Technology, 8.03SC Physics III: Vibrations and Waves, MIT OpenCourseWare, introductory traveling-wave materials.


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 45.20.Dd (Newtonian mechanics)
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