GRE Physics Companion: Angular Velocity and Angular Acceleration as Vectors
The central rigid body kinematics relations are
and
For rotation about a fixed point,
Figure 1. A compact strategy for vector rotational kinematics. Choose a reference point, form the
separation vector, apply the angular-velocity cross product, and include both angular-acceleration
and Normal terms for acceleration.
1 High-value GRE facts
- ω points along the instantaneous rotation axis by the right-hand rule.
- Finite three-dimensional rotations do not generally commute.
- Infinitesimal rotations behave vectorially to first order.
- v = ω ×ρ.
- α = dω∕dt can be nonzero even when |ω| is constant.
- The normal acceleration term is ω × (ω ×ρ).
- For a rigid body, one common ω relates every pair of points.
- vB − vA is perpendicular to rB∕A.
- [ω×] is skew-symmetric.
- Only the component of α parallel to ω changes angular speed.
Part I: Original GRE-style problems
Problem 1: right-hand rule
A disk rotates counterclockwise when viewed from the +z side. Its angular velocity vector
points
- +x
- −x
- +y
- +z
- −z
Problem 2: point velocity
Let
and
Then the point velocity is
- 6ex m∕s
- −6ex m∕s
- 6ey m∕s
- −6ey m∕s
- zero
Problem 3: point on the axis
If ρ is parallel to ω, then the rotational velocity ω ×ρ is
- parallel to ω
- perpendicular to ω with magnitude ωρ
- zero
- equal to ρ
- undefined
Problem 4: changing direction
A body has constant angular speed but the direction of ω changes. Which statement is
correct?
- α = 0
- α must be parallel to ω
- α can be nonzero
- the body cannot be rigid
- the angular speed must increase
Problem 5: normal acceleration
For fixed angular velocity and position ρ perpendicular to the axis,
points
- along ρ
- opposite ρ
- along ω
- tangent to the circle
- out of the plane at random
Problem 6: relative velocity
Points A and B on a rigid body satisfy
Then
is
- 8ex m∕s
- −8ex m∕s
- 8ey m∕s
- −8ey m∕s
- zero
Problem 7: rigidity condition
For two points on a rigid body, the relative velocity vB − vA is always
- parallel to rB∕A
- perpendicular to rB∕A
- zero
- parallel to ω
- equal to rB∕A
Problem 8: skew matrix
The matrix representing cross product with ω satisfies
- [ω×]T = [ω×]
- [ω×]T = −[ω×]
- [ω×]2 = 0 always
- its determinant is always one
- it is diagonal
Problem 9: angular-speed derivative
If α ⊥ ω at an instant, then at that instant
- angular speed is increasing
- angular speed is decreasing
- ω = 0
- ω = 0
- α = 0
Problem 10: finite rotations
Two finite rotations about different axes are generally
- commutative
- noncommutative
- always equivalent to scalar addition
- independent of order only when both are 90∘
- impossible for a rigid body
Problem 11: acceleration with zero angular acceleration
If α = 0 but ω≠0, a point away from the axis has
- zero acceleration
- only the normal double-cross-product acceleration
- only tangential acceleration
- acceleration parallel to velocity
- arbitrary acceleration unrelated to rotation
Problem 12: translating reference point
For a translating and rotating rigid body, the velocity of point B is
- ω × rB∕A only
- vA + ω × rB∕A
- vA + α× rB∕A
- vA + ω2r
B∕A
- always equal to vA
Part II: Complete worked solutions
Solution 1
Counterclockwise rotation viewed from +z corresponds to the right-hand thumb pointing along
+z.
Answer: (D).
Solution 2
| v | = ω ×ρ | (9)
|
| = (3ez) × (2ex) | (10)
|
| = 6ey m∕s. | (11) |
Answer: (C).
Solution 3
Parallel vectors have zero cross product:
Answer: (C).
Solution 4
angular acceleration is the vector derivative
A changing direction produces a nonzero derivative even if the magnitude remains fixed.
Answer: (C).
Solution 5
For ρ ⊥ ω,
Answer: (B).
Solution 6
| vB − vA | = ω × rB∕A | (15)
|
| = (4ez) × (2ex) | (16)
|
| = 8ey m∕s. | (17) |
Answer: (C).
Solution 7
The rigid distance constraint gives
Thus the relative velocity is perpendicular to the separation vector.
Answer: (B).
Solution 8
The cross-product matrix is skew-symmetric:
Answer: (B).
Solution 9
If the vectors are perpendicular, their dot product is zero.
Answer: (C).
Solution 10
Finite rotations about different axes generally depend on order.
Answer: (B).
Solution 11
With α = 0,
Answer: (B).
Solution 12
For two points on the same rigid body,
Answer: (B).
2 GRE checklist
- Apply the right-hand rule before doing component algebra.
- Preserve cross-product order.
- Distinguish angular speed from angular velocity vector.
- Remember that direction change of ω contributes to α.
- For acceleration, include both α× r and the double-cross-product term.
- For translating bodies, include the reference-point velocity or acceleration.
- Use the rigid body orthogonality check rB∕A ⋅ (vB − vA) = 0.
- Recognize [ω×] as a skew-symmetric matrix.
References
References
[1] J. R. Taylor, Classical Mechanics, University Science Books, 2005.
[2] D. Kleppner and R. Kolenkow, An Introduction to Mechanics, 2nd ed., Cambridge
University Press, 2014.
[3] OpenStax, University Physics, Volume 1, Rice University, 2016.