GRE Physics Companion: Scattering Geometry and Impact Parameter
The core scattering relations are
and
Figure 1. A compact strategy for classical scattering problems. Start from b and v∞, determine E
and ℓ, find the turning point or deflection, and convert b(χ) into a cross section when needed.
1 High-value GRE facts
- impact parameter is defined from the incoming asymptote.
- In general, b≠rmin.
- Relative angular momentum is ℓ = μv∞b.
- Head-on scattering has b = 0 and therefore ℓ = 0.
- For U(∞) = 0, the asymptotic relative energy is E =
μv∞2.
- Closest approach is a radial turning point.
- A cross section has dimensions of area.
- An impact-parameter annulus has area dσ = 2πbdb.
- For axial symmetry, dΩ = 2π sin χdχ.
- Hard-sphere scattering has dσ∕dΩ = a2∕4.
Part I: Original GRE-style problems
Problem 1: angular momentum
A reduced particle has μ = 2m, incoming speed v, and impact parameter b. Its angular-momentum
magnitude is
- mvb
- 2mvb
- mv∕b
- 2mv∕b
- zero
Problem 2: head-on collision
For a head-on central-force scattering event,
- b = 0
- b = rmin always
- ℓ≠0
- χ = 0 necessarily
- v∞ = 0
Problem 3: no interaction
If U(r) = 0, then the distance of closest approach is
- 0
- b∕2
- b
- 2b
- infinity
Problem 4: closest approach
At the distance of closest approach in a conservative central scattering problem,
- ṙ = 0
- 𝜃 = 0
- ℓ = 0
- E = 0
- U = 0
Problem 5: geometric cross section
An event occurs whenever b ≤ b0. Its cross section is
- 2πb0
- πb0
- πb02
- 2πb02
- 4πb02
Problem 6: annulus area
The area associated with impact parameters between b and b + db is
- πbdb
- 2πbdb
- 4πbdb
- πb2 db
- db∕b
Problem 7: solid angle
For azimuthally symmetric scattering, the solid-angle element between χ and χ + dχ
is
- 2π dχ
- π sin χdχ
- 2π sin χdχ
- 4π sin χdχ
- sin 2χdχ
Problem 8: hard-sphere grazing
For hard-sphere scattering from radius a, a grazing trajectory has
- b = 0, χ = π
- b = a, χ = 0
- b = a, χ = π
- b = 0, χ = 0
- b = 2a, χ = π∕2
Problem 9: hard-sphere differential cross section
For hard-sphere radius a,
equals
- a2
- a2∕2
- a2∕4
- πa2
- 4πa2
Problem 10: inverse-radius head-on turning point
For repulsive potential U = k∕r and a head-on trajectory, the closest approach is
- k∕E
- E∕k
- 2k∕E
- zero
Problem 11: large impact parameter
For an ordinary short-range interaction, increasing b far beyond the interaction range generally
makes the scattering angle
- larger
- smaller
- exactly π
- undefined
- independent of b
Problem 12: frame issue
The reduced-coordinate scattering calculation most naturally gives
- the center-of-mass or relative scattering geometry
- the laboratory angle of particle 1 in every case
- the laboratory angle of particle 2 in every case
- only total linear momentum
- no angle information
Part II: Complete worked solutions
Solution 1
Use
With μ = 2m,
Answer: (B).
Solution 2
Head-on means the incoming asymptote passes through the force center:
Therefore ℓ = 0. Answer: (A).
Solution 3
For U = 0, the turning-point equation gives
Thus
Answer: (C).
Solution 4
Closest approach is a radial turning point, so
Answer: (A).
Solution 5
The allowed incoming trajectories fill a disk of radius b0:
Answer: (C).
Solution 6
The annulus area is circumference times width:
Answer: (B).
Solution 7
For axial symmetry,
Answer: (C).
Solution 8
A grazing trajectory just touches the sphere:
It experiences vanishing deflection:
Answer: (B).
Solution 9
Hard-sphere geometry gives
Answer: (C).
Solution 10
For b = 0, energy conservation gives
Thus
Answer: (A).
Solution 11
A large impact parameter keeps the trajectory far from a short-range interaction, so the deflection
tends toward zero. Answer: (B).
Solution 12
The reduced-coordinate problem is naturally a center-of-mass or relative-motion calculation.
Laboratory particle angles require an additional frame transformation. Answer: (A).
2 GRE checklist
- Distinguish b from rmin.
- Use ℓ = μv∞b.
- Treat closest approach as a radial turning point.
- Count impact-parameter area with dσ = 2πbdb.
- Use dΩ = 2π sin χdχ for axial symmetry.
- Keep the absolute value in the differential cross section.
- Check hard-sphere limits: b = 0 → χ = π and b = a → χ = 0.
- Distinguish relative or center-of-mass scattering angles from laboratory particle angles.
References
References
[1] J. R. Taylor, Classical Mechanics, University Science Books, 2005.
[2] H. Goldstein, C. Poole, and J. Safko, Classical Mechanics, 3rd ed., Addison-Wesley,
2002.
[3] D. Kleppner and R. Kolenkow, An Introduction to Mechanics, 2nd ed., Cambridge
University Press, 2014.