GRE Physics Companion: Newton’s Law of Universal Gravitation
The essential magnitude law is
For a test mass outside a spherical source mass,
Figure 1. A compact gravitation strategy: define the geometry, apply inverse-square scaling,
determine the force direction, use vector superposition when needed, and convert force to
acceleration or orbital motion.
1 High-value GRE facts
- Gravity is attractive.
- F ∝ m1m2∕r2.
- [G] = N m2 kg−2.
- Equal-and-opposite forces do not imply equal accelerations.
- For free fall, test mass cancels from a = GM∕r2.
- Use center-to-center separation, not altitude alone.
- Multiple gravitational forces add as vectors.
- μ = GM is the gravitational parameter.
- Circular orbital speed is v =
.
- Circular orbital period obeys T2 = 4π2r3∕(GM).
Part I: Original GRE-style problems
Problem 1: inverse-square scaling
If the separation between two masses doubles while the masses remain fixed, the gravitational force
becomes
- twice as large
- unchanged
- one half as large
- one fourth as large
- one eighth as large
Problem 2: changing mass and distance
If m1 is doubled and the separation is tripled, the new force relative to the original
is
- 2∕3
- 2∕9
- 3∕2
- 6
- 18
Problem 3: action and reaction
Two unequal masses attract gravitationally. The force magnitude on mass 1 due to mass 2
is
- greater than the force on mass 2
- less than the force on mass 2
- equal to the force on mass 2
- zero if mass 1 is smaller
- proportional only to mass 1
Problem 4: acceleration ratio
If m2 = 4m1, the ratio of acceleration magnitudes is
equal to
- 1∕4
- 1∕2
- 1
- 2
- 4
Problem 5: free fall
Ignoring air resistance, two test objects of different mass at the same location near a source body
have gravitational accelerations that are
- proportional to their masses
- inversely proportional to their masses
- equal
- zero for the lighter object
- equal only if their volumes match
Problem 6: altitude
At altitude h = RE above Earth’s surface, the spherical-Earth gravitational acceleration
is
- g0
- g0∕2
- g0∕3
- g0∕4
- g0∕8
Problem 7: symmetric superposition
Two equal source masses are placed symmetrically on opposite sides of a test mass. At the exact
midpoint the net gravitational force is
- toward the left mass
- toward the right mass
- zero
- infinite
- twice one individual force
Problem 8: gravitational parameter
The gravitational parameter of a body is
- G∕M
- GM
- G∕M2
- M∕G
- Gr
Problem 9: circular orbit
The circular orbital speed around a much larger central mass is
- GM∕r
- 2πGM∕r
- GM∕r2
Problem 10: circular period scaling
For circular orbits around the same central mass,
scales with radius as
- T ∝ r−2
- T ∝ r−1∕2
- T ∝ r
- T ∝ r3∕2
- T ∝ r2
Problem 11: vector direction
If
the force on mass 1 due to mass 2 points
- along +r12
- along −r12
- perpendicular to r12
- in an arbitrary direction
- opposite to both positions
Problem 12: dimensions of G
The dimensions of G are
- N mkg−1
- N m2 kg−2
- N kg−2
- ms−2
- kg m2 s−2
Part II: Complete worked solutions
Solution 1
Because
doubling distance gives
Answer: (D).
Solution 2
The mass change contributes a factor 2, while tripling distance contributes 1∕9:
Answer: (B).
Solution 3
Newton’s third law requires the interaction forces to have equal magnitude and opposite direction.
Answer: (C).
Solution 4
Equal force magnitudes give
Thus
Answer: (E).
Solution 5
The test mass cancels:
so
Answer: (C).
Solution 6
At h = RE, the center-to-center distance is 2RE, so
Answer: (D).
Solution 7
The equal force vectors point in opposite directions and cancel. Answer: (C).
Solution 8
By definition,
Answer: (B).
Solution 9
Equate gravitational force to centripetal force:
Therefore
Answer: (C).
Solution 10
Kepler’s circular-orbit result is
so
Answer: (D).
Solution 11
The vector r12 points from mass 1 toward mass 2, exactly the direction of the attractive force on
mass 1. Answer: (A).
Solution 12
From
the units are
Answer: (B).
2 GRE checklist
- Use center-to-center distance.
- Apply inverse-square scaling before doing full arithmetic when possible.
- Distinguish equal forces from unequal accelerations.
- Use vectors for multiple source masses.
- Cancel the test mass in free-fall acceleration.
- Use μ = GM when orbital formulas are written compactly.
- Derive circular speed by equating gravity and centripetal force.
References
References
[1] PhysicsLibrary, M07-01, Newton’s Law of Universal Gravitation.
[2] J. R. Taylor, Classical Mechanics, University Science Books, 2005.
[3] D. Kleppner and R. Kolenkow, An Introduction to Mechanics, 2nd ed., Cambridge
University Press, 2014.