GRE Physics Companion: Work Done by a Force
The fastest way to solve most work questions is to begin with the dot product
The angle is always the angle between the force and the displacement. Do not automatically use the
angle drawn relative to the horizontal or vertical unless that is also the angle between force and
displacement.
1 Fast triage
Figure 1. GRE work triage: identify the displacement, isolate the force being asked about,
determine the angle between them, and then evaluate the dot product.
High-value shortcuts are
and
2 Cosine controls the sign
Figure 2. The sign of work follows the sign of the cosine of the angle between force and
displacement. Perpendicular force and displacement give zero work.
This makes angle questions extremely fast. If a force becomes more nearly parallel to the
displacement while F and Δr stay fixed, its work increases. If it becomes more nearly
perpendicular, its work approaches zero.
3 Component shortcut
When vectors are given in components, skip angle reconstruction and use
This avoids unnecessary inverse trigonometric calculations.
4 Worked GRE example 1: rank forces by work
Three forces of equal magnitude F act through the same displacement d. Their angles
between force and displacement are 0∘, 60∘, and 120∘. Rank their works from greatest to
least.
Because
we have
Therefore
The negative result is smaller than zero, not merely smaller in magnitude.
5 Worked GRE example 2: component dot product
A force and displacement are
Then
Thus
No angle calculation is needed.
6 GRE practice questions
- A constant force of magnitude F acts through displacement d. If the force is
perpendicular to the displacement, what is the work?
- A force of magnitude F acts at 60∘ to a displacement d. Express the work in terms of
F and d.
- The angle between force and displacement changes from 60∘ to 120∘ while F and d
remain fixed. How does the work change?
- A particle moves in a circle under a force that is always directed toward the center.
What work does that force do over one revolution?
- A constant 5 N force acts in the +x direction while a particle moves 3 m in the −x
direction. Find the work.
- A constant force acts on a particle. The magnitude of the force doubles and the
displacement magnitude triples, while the angle between force and displacement
remains unchanged. By what factor does the work change?
7 Answers
- Zero.
- Fd∕2.
- It changes from +Fd∕2 to −Fd∕2.
- Zero, because the radial force is perpendicular to each tangential displacement.
- −15 J.
- Factor of 6.
8 Final checklist
- Work is a scalar.
- Use the angle between force and displacement.
- Parallel gives maximum positive work.
- Perpendicular gives zero work.
- Antiparallel gives maximum negative work.
- Use components directly when they are supplied.
- Separate work by one force from net work by all forces.
- Area under an Fx versus x graph is signed work.
References
[1] PhysicsLibrary, M03-01, Work Done by a Force.
[2] OpenStax, University Physics, Volume 1, sections on work and kinetic energy, CC
BY 4.0.