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motion in central-force field
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(Definition)
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Let us consider a body with mass in a gravitational force field exerted by the origin and directed always from the body towards the origin. Set the plane through the origin and the velocity vector of the body. Apparently, the body is forced to move constantly in this plane, i.e. there is a question of a planar motion. We want to derive the trajectory of the body.
Equip the plane of the motion with a polar coordinate system
and denote the position vector of the body by . Then the velocity vector is
 |
(1) |
where
and
are the unit vectors in the direction of and of rotated 90 degrees anticlockwise (
, whence
). Thus the kinetic energy of the body is
Because the gravitational force on the body is exerted along the position vector, its moment is 0 and therefore the angular momentum
of the body is constant; thus its magnitude is a constant,
whence
 |
(2) |
The central force
(where is a constant) has the scalar potential
. Thus the total energy
of the body, which is constant, may be written
This equation may be revised to
i.e.
where
is a constant. We introduce still an auxiliary angle such that
 |
(3) |
Differentiation of the first of these equations implies
whence, by (2),
This means that
, where the constant is determined by the initial conditions. We can then solve from the first of the equations (3), obtaining
 |
(4) |
where
The result (4) shows that the trajectory of the body in the gravitational field of one point-like sink is always a conic section whose focus contains the sink causing the field.
As for the type of the conic, the most interesting one is an ellipse. It occurs when
. This condition is easily seen to be equivalent with a negative total energy of the body.
One can say that any planet revolves around the Sun along an ellipse having the Sun in one of its foci — this is Kepler's first law.
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"motion in central-force field" is owned by pahio.
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See Also: Kepler's first two laws of planetary motion, Kepler's third law of planetary motion, Kepler's three laws of planetary motion summarized
Other names: |
Kepler's first law |
This object's parent.
Cross-references: field, section, energy, scalar, magnitude, angular momentum, kinetic energy, unit vectors, position vector, system, motion, vector, velocity
There is 1 reference to this object.
This is version 6 of motion in central-force field, born on 2009-03-31, modified 2009-04-04.
Object id is 615, canonical name is MotionInCentralForceField.
Accessed 497 times total.
Classification:
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Pending Errata and Addenda
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