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[parent] quarter loop example of Biot-Savart law

(Example)

A simple example of the Biot-Savart law is given with a current carrying loop for a quater of a circle as shown in Figure 1.

PIC

Figure 1. Quarter Current Loop

The differential line element dl is perpendicular to r, so the Biot-Savart law simplifies from the definition of the cross product

dB  = − -μ0Idl-sin(π∕2)kˆ
        4 π     r2

Note that the direction is into the web browser, so we have a −k. For the differential dl of a circular arc

dl = rd 𝜃

plugging this in and setting up the integral gives

        μ  I∫  π2
B  = − ˆk--0-     d𝜃
        4πr   0

which simply yields

       μ0Iˆk-
B =  −  8r

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Cross-references: cross product, Biot-Savart law
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This is version 4 of quarter loop example of Biot-Savart law, born on 2006-01-14, modified 2026-09-05.
Object id is 104, canonical name is QuarterLoopExampleOfBiotSavartLaw.
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Classification:
Physics Classification: 41.20.Gz (Magnetostatics; magnetic shielding, magnetic induction, boundary-value problems)

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