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point division and position vectors (Topic)

Point Division, Affine Combinations, Ceva, and Menelaus

Let $P$ divide the directed segment $AB$ internally in the ratio $m:n$, meaning

$\displaystyle \frac{AP}{PB}=\frac{m}{n}. $
With position vectors $\mathbf{a},\mathbf{b},\mathbf{p}$, the modern section formula is

$\displaystyle \boxed{\mathbf{p}=\frac{n\mathbf{a}+m\mathbf{b}}{m+n}}. \tag{1} $
The midpoint is the special case

$\displaystyle \mathbf m=\frac{\mathbf{a}+\mathbf{b}}{2}. \tag{2} $
Image brand_fig_7a
Figure 7a, modernized: point division and position vectors.

Midpoints of two vectors

If $M$ and $N$ are the midpoints of $AA'$ and $BB'$, then

$\displaystyle \overrightarrow{MN} =\frac12\left(\overrightarrow{AB}+\overrightarrow{A'B'}\right). $
Image brand_fig_7b
Figure 7b, modernized: midpoint theorem for two directed segments.

Affine dependence

If

$\displaystyle a\mathbf{a}+b\mathbf{b}+c\mathbf{c}=\mathbf0, \qquad a+b+c=0, $
with nonzero coefficients, then the points $A,B,C$ are collinear. Similarly, if four position vectors satisfy a nontrivial relation whose coefficients sum to zero, the four points are coplanar.

Ceva's theorem

For points $L\in BC$, $M\in CA$, and $N\in AB$, the cevians $AL$, $BM$, and $CN$ are concurrent precisely when the directed division ratios satisfy

$\displaystyle \frac{BL}{LC}\frac{CM}{MA}\frac{AN}{NB}=1. $
Brand derives this efficiently by expressing the intersection point as an affine combination of the vertex position vectors.
Image brand_fig_7c
Figure 7c, modernized: concurrent cevians used in the vector proof of Ceva's theorem.

Menelaus's theorem

For a transversal meeting the extended sides of triangle $ABC$ at $L,M,N$, the directed ratios obey

$\displaystyle \frac{BL}{LC}\frac{CM}{MA}\frac{AN}{NB}=-1. $
Image brand_fig_7d
Figure 7d, modernized: transversal geometry used in Menelaus's theorem.

Centroid geometry

The medians of a triangle are concurrent at the centroid $G$, and

$\displaystyle \mathbf r_G=\frac{\mathbf{r}_A+\mathbf{r}_B+\mathbf r_C}{3}. $
Each median is divided by $G$ in the ratio $2:1$ measured from the vertex.
Image brand_fig_7e
Figure 7e, modernized: medians and centroid of a triangle.

For a tetrahedron, the segments joining the midpoints of opposite edges meet at their common midpoint.

Image brand_fig_7f
Figure 7f, modernized: midpoint geometry in a tetrahedron.

Source problems

  1. If $P,Q,R$ are the midpoints of the sides of triangle $ABC$, prove for any origin $O$ that

    $\displaystyle \overrightarrow{OA}+\overrightarrow{OB}+\overrightarrow{OC} =\overrightarrow{OP}+\overrightarrow{OQ}+\overrightarrow{OR}. $
  2. For quadrilateral $ABCD$, with $P,Q$ the midpoints of $AC,BD$ and $M$ the midpoint of $PQ$, prove

    $\displaystyle \overrightarrow{AB}+\overrightarrow{AD}+\overrightarrow{CB}+ \overrightarrow{CD}=4\overrightarrow{PQ}, $
    and

    $\displaystyle \overrightarrow{OA}+\overrightarrow{OB}+\overrightarrow{OC}+ \overrightarrow{OD}=4\overrightarrow{OM}. $
  3. Prove the $2:1$ centroid division theorem for a triangle and $\mathbf r_G=(\mathbf{r}_A+\mathbf{r}_B+\mathbf r_C)/3$.
  4. If $G,G'$ are the centroids of triangles $ABC,A'B'C'$, prove

    $\displaystyle \overrightarrow{AA'}+\overrightarrow{BB'}+\overrightarrow{CC'} =3\overrightarrow{GG'}. $
  5. If $E,F$ are midpoints of $AB,BC$ in parallelogram $ABCD$, prove the lines $DE,DF$ trisect diagonal $AC$ in the manner described by Brand.
  6. If $A,B,C,D$ are the midpoints of the successive sides of any space quadrilateral, prove

    $\displaystyle \overrightarrow{AB}=\overrightarrow{DC},\qquad \overrightarrow{AD}=\overrightarrow{BC}. $
  7. Prove the midpoint theorem for opposite edges of a tetrahedron shown in Figure 7f.
  8. If $G$ is the centroid of $A,B,C$ and $M$ the mean center of $A,B,C,D$, prove that $M$ divides $DG$ in the ratio $3:1$.
  9. Prove Desargues's theorem using affine vector relations: if triangles $ABC$ and $A'B'C'$ are perspective from a point, then the intersections of corresponding sides are collinear.

Modern notation references

The notation and terminology in this modernized article follow standard present-day mechanics and vector-analysis usage, particularly:
  1. J. R. Taylor, classical mechanics, University Science Books, 2005.
  2. D. Kleppner and R. Kolenkow, An Introduction to Mechanics, 2nd ed., Cambridge University Press, 2014.
  3. H. Goldstein, C. Poole, and J. Safko, Classical Mechanics, 3rd ed., Addison–Wesley, 2002.

Source

This article is a modernized restatement of the corresponding Public domain article in Louis Brand, Vectorial Mechanics, John Wiley & Sons, New York, 1930, Chapter I, “Vector Algebra.” The original 1930 edition is the source basis.



"point division and position vectors" is owned by bloftin.
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See Also: scalar multiplication of vectors, vector subtraction and position vectors, negative of a vector, equality of vectors, vector, vector algebra, vector addition, vectors in a plane

Also defines:  section formula, vector midpoint, affine dependence, Ceva's theorem, Menelaus's theorem, vector centroid geometry

Cross-references: domain, classical mechanics, mechanics, vector, relation, theorem, position vectors

This is version 1 of point division and position vectors, born on 2026-08-20.
Object id is 1072, canonical name is PointDivisionAndPositionVectors.
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Physics Classification02. (Mathematical methods in physics)
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