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[parent] moment of inertia of a circular disk (Example)

Here we look at two cases for the moment of inertia of a homogeneous circular disk

(a) about its geometrical axis,

(b) about one of the elements of its lateral surface.

Let m be the mass, a the radius, l the thickness, and τ the density of the disk. Then choosing a circular ring for the element of mass we have

dm  = τ ⋅ l ⋅ 2πr ⋅ dr

where r is the radius of the ring and dr its thickness.

PIC

Therfore the moment of inertia about the axis of the disk is

         ∫
           a  3
I = 2 πlτ    r dr
          0

    τlπa4
I = ------
      2

     ma2--
I =   2

The moment of inertia about the element is obtained easily by the help of theorem II. Thus

I′ = I + ma2

  ′  3-   2
I  = 2 ma

It will be noticed that the thickness of the disk does not enter into the expressions for I and I except through the mass of the disk. Therefore these expressions hold good whether the disk is thick enough to be called a cylinder or thin enough to be called a circular lamina.

0.1 References

This article is a derivative of the public domain book, ”Analytical mechanics” by Haroutune M. Dadourian, 1913. Made available by the internet archive


"moment of inertia of a circular disk" is owned by bloftin.
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Other names:  rotational inertia of a circular disk

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Cross-references: mechanics, domain, theorem, mass, moment of inertia

This is version 3 of moment of inertia of a circular disk, born on 2006-07-11, modified 2006-07-11.
Object id is 197, canonical name is MomentOfInertiaOfACircularDisk.
Accessed 8614 times total.

Classification:
Physics Classification45.40.-f (Dynamics and kinematics of rigid bodies)
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