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[parent] lamellar field (Topic)

A vector field   $\vec{F} = \vec{F}(x,\,y,\,z)$,  defined in an open set $D$ of $\mathbb{R}^3$, is  lamellar  if the condition

$\displaystyle \nabla\!\times\!\vec{F} = \vec{0}$
is satisfied in every point   $(x,\,y,\,z)$  of $D$.

Here, $\nabla\!\times\!\vec{F}$ is the curl or rotor of $\vec{F}$.  The condition is equivalent with both of the following:

  • The line integrals

    $\displaystyle \oint_s \vec{F}\cdot d\vec{s}$
    taken around any closed contractible curve $s$ vanish.
  • The vector field has a scalar potential  $u = u(x,\,y,\,z)$  which has continuous partial derivatives and which is up to a constant term unique in a simply connected domain; the scalar potential means that

    $\displaystyle \vec{F} = \nabla u.$
The scalar potential has the expression

$\displaystyle u = \int_{P_0}^P\vec{F}\cdot d\vec{s},$
where the point $P_0$ may be chosen freely,  $P = (x,\,y,\,z)$.

Note.  In physics, $u$ is in general replaced with  $V = -u$.  If the $\vec{F}$ is interpreted as a force, then the potential $V$ is equal to the work made by the force when its point of application is displaced from $P_0$ to infinity.



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"lamellar field" is owned by pahio.

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Cross-references: work, scalar, domain, curl, vector field
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This is version 1 of lamellar field, born on 2008-08-27.
Object id is 292, canonical name is LamellarField.
Accessed 449 times total.

Classification:
Physics Classification02.30.Em (Potential theory)
 45.20.Dd (Newtonian mechanics)

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