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Fourier series in complex form and Fourier integral
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(Topic)
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The Fourier series expansion of a Riemann integrable real function on the interval is
 |
(1) |
where the coefficients are
 |
(2) |
If one expresses the cosines and sines via Euler formulas with exponential function, the series (1) attains the form
 |
(3) |
The coefficients could be obtained of and , but they are comfortably derived directly by multiplying the equation (3) by
and integrating it from to . One obtains
 |
(4) |
We may say that in (3), has been dissolved to sum of harmonics (elementary waves)
with amplitudes corresponding the frequencies .
For seeing how the expansion (3) changes when
, we put first the expressions (4) of to the series (3):
By denoting
and
, the last equation takes the form
It can be shown that when
and thus
, the limiting form of this equation is
 |
(5) |
Here, has been represented as a Fourier integral. It can be proved that for validity of the expansion (4) it suffices that the function is piecewise continuous on every finite interval having at most a finite amount of extremum points and that the integral
converges.
For better to compare to the Fourier series (3) and the coefficients (4), we can write (5) as
 |
(6) |
where
 |
(7) |
If we denote
as
 |
(8) |
then by (5),
 |
(9) |
is called the Fourier transform of . It is an integral transform and (9) represents its inverse transform.
N.B. that often one sees both the formula (8) and the formula (9) equipped with the same constant factor
in front of the integral sign.
- 1
- K. V¨AISÄLÄ: Laplace-muunnos. Handout Nr. 163. Teknillisen korkeakoulun ylioppilaskunta, Otaniemi, Finland (1968).
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"Fourier series in complex form and Fourier integral" is owned by pahio.
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Other names: |
complex Fourier series and integral |
Keywords: |
Fourier series, Fourier integral |
Cross-references: formula, Fourier transform, waves, function
This is version 2 of Fourier series in complex form and Fourier integral, born on 2009-04-18, modified 2009-04-18.
Object id is 650, canonical name is FourierSeriesInComplexFormAndFourierIntegral.
Accessed 454 times total.
Classification:
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Pending Errata and Addenda
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