The mean translational kinetic energy is a result from the Maxwell-Boltzmann distribution and is given by
 ( 1)
A more useful form of this equation is in terms of temperature. Temperature is brought in through the root mean square speed derived in the kinetic thoery of gases
 ( 2)
where R is the gas constand
![$\displaystyle R = 8.31 \, [ \frac{J}{mol * K} ] $ $\displaystyle R = 8.31 \, [ \frac{J}{mol * K} ] $](http://images.physicslibrary.org/cache/objects/23/l2h/img3.png) ( 3)
and more to come ...
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