The angle of rotation can be found from the trace of the direction cosine matrix to axis angle of rotation matrix
Noting that the axis of rotation is a unit vector and has a length of 1 means
therefore
rearranging gives
 |
(1) |
Inverse cosine is a multivalued function and there are 2 possible solutions for . Normally, the convention is to choose the principle value such that

As long as is not zero, the unit vector is given by
![$\displaystyle \left[ \begin{array}{c} e_1 \ e_2 \ e_3 \end{array} \right] =... ...2 sin(\alpha)} \ \dfrac{(A_{12} - A_{21})}{2 sin(\alpha)} \end{array} \right]$ $\displaystyle \left[ \begin{array}{c} e_1 \ e_2 \ e_3 \end{array} \right] =... ...2 sin(\alpha)} \ \dfrac{(A_{12} - A_{21})}{2 sin(\alpha)} \end{array} \right]$](http://images.physicslibrary.org/cache/objects/89/l2h/img8.png) |
(2) |
Above equation should be proved at some time...
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