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determinant (Definition)

In attempting to solve a linear system of equations for x1, x2 and x3

a1x1 + b1x2 + c1x3  =  d1
a2x1 + b2x2 + c2x3  =  d2
   1      2      3
a3x  + b3x +  c3x   =  d3
(1)

one is led in a very natural way to consider the square array

||  1   1   1 ||
| a12  a22  a32 |
|| a1  a2  a3 ||
| a31  a32  a33 |
(2)

We have written aij = aji,i,j = 1, 2, 3. The solution of (1) requires that we attach a numerical value to the matrix of elements (2). We do this in the following way: We attach 33 = 27 numerical values to a set of 𝜖ijk,i,j,k = 1, 2, 3. If at least two of the superscripts in 𝜖ijk are the same, the value of 𝜖ijk is zero. Thus 𝜖223 = 𝜖131 = 𝜖333 = 0, etc. If the i, j, k are all different, the value of 𝜖ijk is to be +1 or 1 according to whether it takes an even or odd number of permutations to rearrange the ijk into the natural order 123. Let us lood at 𝜖321 and hence at the arrangement 321. Permuting the integers 2 and 3 permutes 321 into 231, then permuting 3 and 1 permutes 231 into 213, and finally 213 permutes into 123 if we interchange the integers 2 and 1. Three (an odd number) permutations were required to permute 321 into 123. Thus 𝜖123 = 1. We have

𝜖123 = 𝜖312 = 𝜖231 = +1

𝜖213 = 𝜖321 = 𝜖132 = − 1

We now define

|           |
||a11  a12  a13 ||
|a21  a22  a23 | ≡ 𝜖ijka1ia2ja3k
||a3  a3  a3 ||
  1   2   3
(3)

The letters i, j, k are indices of summation. Equation (3) defines the determinant of the square matrix of elements (2) Its numerical value is given by the right-hand side of (3). It consists, in general, of 3! = 3 2 1 = 6 terms, each term a product of three elements, one element from each row and column of (3). Expand (3) to get

𝜖ijka1a2a3 = (a1a2 a3+ a1a2 a3+ a1a2 a3) − (a1a2a3 + a1a2a3 + a1a2a3)
    i j  k     1 2 3    3 1 2    2 3 1     2 1 3    3 2 1    1 3 2

Only 3! = 6 terms occur in the exapansion of (3) since there are 3! permutations of 123. All other values of 𝜖ijk are zero.

We can define 𝜖ijk in exactly the same manner in which the 𝜖ijk were defined. We leave it to the reader to show that

 ijk 1 2 3       i  j k
𝜖  aiajak = 𝜖ijka1a 2a 3

The generalization of second and third order determinants (the order of a determinant is the number of rows or columns of the determinant) to the nth order determinants is simple. We define the 𝜖i1i2⋅⋅⋅in to have the following numerical values: 𝜖i1i2⋅⋅⋅in = 0 if at least two of the superscripts are the same. The values of the superscripts range from 1 to n. If the i1,i2,…,in are distinct, the value of 𝜖i1i2⋅⋅⋅in is to be +1 or 1 depending on whether an even or odd number of permutations is required to rearrange i1,i2,…,in into the natural order 123⋅⋅ ⋅n. The numerical value (determinant) of the square array of elements ∥   ∥
∥aij∥, i,j = 1, 2,…,n, is defined as

      |                    |
      |  a1   a1  ...  a1  |
|  |  ||   12    22        n2  ||
|aij| = || a1   a2  ...  an  ||
      | ...  ...  ...  ... |
      |  an1  an2  ...  ann  |

|  |
|aij| = 𝜖i1i2⋅⋅⋅ina1ia2i ⋅⋅⋅ani
               1  2     n
|  |
|aij| = 𝜖i1i2⋅⋅⋅inai11 ai22⋅⋅⋅ainn
(4)

where the 𝜖i1i2⋅⋅⋅in are defined in precisely the same manner in which the 𝜖i1i2⋅⋅⋅in are defined. In general, (4) consists of n! terms, each term a product of elements, one element fom each row and column of |  |
|aij|.

To facilitate writing, we shall deal with third order determinants, but it will be obvious to the reader that any theorem derived for third order determinants will apply to determinants of any finite order. Le us consider

     ||  1   1   1 ||
     | a1  a2 a 3 |                     j
Δ =  || a21  a22 a23 ||= 𝜖ijka1ia2ja3k = 𝜖ijkai1a2ak3
     | a31  a32 a33 |
(5)

We can obtain a new third order determinant by interchanging the first and third row of Δ. This yields

     |            |
     | a31  a32  a33 |
Δ ′ = || a2 a2  a2 ||=  𝜖ijka3a2a1
     ||  11   21   31 ||       i j k
       a1  a2  a3
(6)

But 𝜖ijka i3a j2a k1 = 𝜖ijka k1a j2a i1 = 𝜖kjia i1a j2a k3, since i amd k are dummy indices. We see that every term of (6) is the same as every term in (5) with the exception that 𝜖ijk is replaced by 𝜖kji. Since 𝜖ijk = 𝜖kji, we conclude that Δ = Δ. we thus obtain the following theorems:

THEOREM 1.1. Interchanging two rows (or columns) of a determinant changes the sign of the determinant.

THEOREM 1.1. If two rows (or columns) of a determinant are the same, the value of the determinant is zero.

We note that

     |              |
     || la11  la12  la13 ||
Δ′′ = || a21  a22   a23 || = 𝜖ijk(la1i)a2ja3k = lΔ
     |  a3  a3   a3 |
         1   2    3
(7)

THEOREM 1.3. If a row (or column) of a determinant is multiplied by a factor l, the value of the determinant is thereby multiplied by l.

Let us now investigate the determinant

       ||  1    3   1     3   l    3 ||
       |a 1 + la1 a2 + la 2 a 3 + la3 |
Δ ′′′ = ||   a21        a22       a23    ||
       |   a31        a32       a33    |

Δ ′′′ = 𝜖ijk(a1 + la3)a2a3
            i    i  j k

Δ ′′′ = 𝜖ijka1a2a3 + l𝜖ijka3a2a3
           i j k        i j k
 ′′′
Δ  =  Δ
(8)

since 𝜖ijka i3a j2a k3 = 0 from Theorem (1.2). Hence we obtain the following theorem:

THEOREM 1.4. The value of a determinant remains unchanged if to the elements of any row (or column) is added a scalar multiple of the corresponding elements of another row (or column).

The theorems derived above are very useful in evaluating a determinant.

1 References

[1] Lass, Harry. ”Elements of pure and applied mathematics” New York: McGraw-Hill Companies, 1957.

This entry is a derivative of the Public domain work [1].


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This is version 2 of determinant, born on 2010-02-21, modified 2010-02-21.
Object id is 844, canonical name is Determinant.
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