For a simple one dimensional example of the relationship between force and potential energy, assume that the potential energy of a particle is given by the equation
The realtionship between force and potential energy is
 |
(1) |
For our 1D example, where the potential energy is dependent only on the position, 
Taking the derivative yields
Therefore, the force on the particle is governed by the equation
![$\displaystyle F = -\frac{A}{x^2} \left [ 1 + B e^{-x/c} \right ] + \frac{A}{x} \left [ -\frac{B}{C}e^{-x/c} \right ]$ $\displaystyle F = -\frac{A}{x^2} \left [ 1 + B e^{-x/c} \right ] + \frac{A}{x} \left [ -\frac{B}{C}e^{-x/c} \right ]$](http://images.physicslibrary.org/cache/objects/261/l2h/img6.png) |
(2) |
If we further assume that the constant C is so much larger than x, the force will simplify. Rearraning to get
Because ,
, we get
Further simplifying
gives the force under this assumption
![$\displaystyle F = -\frac{A}{x^2} \left [ 1 + B \right ]$ $\displaystyle F = -\frac{A}{x^2} \left [ 1 + B \right ]$](http://images.physicslibrary.org/cache/objects/261/l2h/img12.png) |
(3) |
|