|
Main Menu
|
Sections
Talkback
Downloads
Information
|
|
|
|
|
dot product examples
|
(Example)
|
|
Examples involving the dot product:
(1) Calculate
with


answer:


(2) Find the angle between the above vectors.
answer:
We know their dot product, so we just need to calculate their magnitudes




Finally




|
Anyone with an account can edit this entry. Please help improve it!
"dot product examples" is owned by bloftin.
|
|
This object's parent.
Cross-references: magnitudes, vectors, dot product
This is version 2 of dot product examples, born on 2006-07-22, modified 2006-07-22.
Object id is 207, canonical name is DotProductExample.
Accessed 2815 times total.
Classification:
|
|
|
|
Pending Errata and Addenda
|
|
|
|
|
|
|
|