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| ``Re: Question about B-field at center of loop''
by evanm3 on 2011-01-18 14:30:39 |
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| Thanks for your reply. Interestingly enough the equation does have a pi in the denominator. This is how the code reads: $\displaystyle {\bf B} = \frac{\mu_0 I \hat{{\bf k}}}{2 \pi r} $.
Thanks again for your response. I just wanted to make sure I was solving for the B field correctly. I'm glad I came across your site -- it's helped a lot. |
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