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Viewing Message ``Re: Ponder October 2007'' by dh2718 on 2007-10-11 03:44:58 Well, good morning. I repeat here my partial response to Parashar's challenge. For the tetrahedron the answer is 1/2 and for the cube it is 7/12. I give up for the over polyhedra, my spatial vision is too weak. Besides, each polyhedron demands a special treatment; the symmetries of the tetrahedron, for example, don't help to solve the cube's problem. "Brute force" here means, I guess, using a circuit simulation program like Pspice, which gives the answers at a glance, with decimal numbers. A few years ago, I submitted to IBM a similar challenge: to find the resistance between two opposite vertices of an n-dimensional hypercube (5/6 for the 3-dimension cube). They didn't accept it; I guess that they don't like n-dimensional spaces where spatial intuition cannot work. [ reply | up | top ] Interact reply

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